10n^2-75n+140=)

Solution for 10n^2-75n+140=) equation:

10n^2-75n+140=)

We move all terms to the left:

10n^2-75n+140-())=0

We add all the numbers together, and all the variables

10n^2-75n=0

a = 10; b = -75; c = 0;
Δ = b2-4ac
Δ = -752-4·10·0
Δ = 5625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5625}=75$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-75)-75}{2*10}=\frac{0}{20}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-75)+75}{2*10}=\frac{150}{20}
=7+1/2
$